Persamaan garis lurus yang melalui titik p(6,-4) dan bergradien 1/3

jawab
p(6,-4)
m = 1/3
y - y1 = m(x - x1)
y - (-4) = 1/3 (x - 6)
y + 4 = 1/3 ( x - 6)
3(y + 4)= 1 ( x - 6)
3y + 12 = x - 6
x - 3y - 6 - 12 = 0
x - 3y - 18= 0