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6.)
200 °C = (9/5 × 200) + 32 °F
= 360 + 32 °F
= 392 °F

7.)
-40 °C = 4/5 × -40 °R
= -32 °R

-40 °C = (9/5 × -40) + 32 °F
= -72 + 32 °F
= -40 °F

8.)
50 °F = {(50 - 32) × 5/9} + 273 K
= (18 × 5/9) + 273 K
= 10 + 273 K
= 283 K

9.)
253 K = {(253 - 273) × 9/5} + 32 °F
= (-20 × 9/5) + 32 °F
= -36 + 32 °F
= -4 °F