Matematika

Pertanyaan

p log (x²-12)=p log x

1 Jawaban

  • x² - 12 = x
    x² - x -12 = 0
    (x-4)(x+4) = 0
    x-4 = 0
    x= 4

    x+4=0
    x = -4

    kolom komentar
    ²log(x.(x-6)) = ²log 16
    x² - 6x = 16
    x² - 6x - 16 = 0
    (x-8) (x+2) = 0
    x-8=0
    x=8

    x+2=0
    x=-2

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