Jika di ketahui tan 10 derajat = 5/p. Tentukan sin 10 derajat dan sec 80 derajat

jawab

tan10 = 5/p
tan 10 = y/x
 
misal 
y = 5
x = p
r = √(x² + y²)= √(p²+25)

sin 10 = y/r = 5/√(p²+25)
cos 80 = cos (90-10) = sin 10
sec 80 = cosec 10 = 1/sin10 = √(p²+25)/5