tolong bantuannya kakak-kakak!!!

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4(3a + 2) = (4 × 3a) + (4 × 2) = 12a + 8

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(x + 3)(x - 2)
= x(x - 2) + 3(x - 2)
= x² - 2x + 3x - 6
= x² + x - 6

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(2x - 1)(x + 2y - 3)
= 2x(x + 2y - 3) - 1(x + 2y - 3)
= 2x² + 4xy - 6x - x - 2y + 3
= 2x² + 4xy - 7x - 2y + 3

a. 4(3a + 2)
= 12a + 8
b. (x+3) - (x-2)
= x² + 2x + 3x +6
= x² + 5x + 6
c. (2x -1) (x +2y - 3)
= 2x² + 4xy - 6x - x - 2y + 3
= 2x² + 4xy - 7x - 2y + 3


smga mmbantu ya