tolong dong isi yang ini

1. 10√2
2. 7√5
3. 5√2
 sepertinya begituu

Mapel : Matematika
Materi : Akar - Operasi Penjumlahan dan Pengurangan

Perlu diingat :
→ (m√a) + (n√a) = (m + n) √a 
→ (m√a) - (n√a) = (m - n) √a
→ Jika bilangan di dalam tanda akar masih bisa disederhanakan, sederhanakan dulu hingga ke bilangan yang tidak mengandung unsur kuadrat.

[tex]\bold{1)\ 3\sqrt{2}+7\sqrt{2}}=(3+7) \sqrt{2}=\bold{10\sqrt{2}}\\ \\\bold{2)\ 9\sqrt{5}-2\sqrt{5}}=(9-2)\sqrt{5}=\bold{7\sqrt{5}}\\ \\\bold{3)\ 4\sqrt{2}-2\sqrt{2}+3 \sqrt{2}}=(4-2+3)\sqrt{2}= \bold{5\sqrt{2}}[/tex]

[tex]\bold{4)\ 7\sqrt{50}-2\sqrt{18}-2\sqrt{32}}\\=(7\sqrt{25\times2})-(2\sqrt{9\times2})-(2\sqrt{16\times2})\\=(7\sqrt{5^2\times2})-(2\sqrt{3^2\times2})-(2\sqrt{4^2\times2})\\=(7\times5)\sqrt{2}-(2\times3)\sqrt{2}-(2\times4)\sqrt{2}\\ =35\sqrt{2}-6\sqrt{2}-8\sqrt{2}\\=(35-6-8) \sqrt{2}\\= \bold{21\sqrt{2}}[/tex]

[tex]\bold{5)\ \sqrt{48}-\sqrt{75}+\sqrt{147}}\\=\sqrt{(16\times3)}-\sqrt{(25\times3)}+\sqrt{(49\times3)}\\=\sqrt{4^2\times3}-\sqrt{5^2\times3}+\sqrt{7^2\times3}\\=4\sqrt{3}-5\sqrt{3}+7\sqrt{3}\\=(4-5+7) \sqrt{2} \\ =\bold{6\sqrt{2}}[/tex]

[tex]\bold{6)\ 4\sqrt{5}-\sqrt{20}+\sqrt{45}}\\=4\sqrt{5}-\sqrt{(4\times5)}+\sqrt{(9\times5)}\\=4\sqrt{5}-\sqrt{2^2\times5}+(\sqrt{3^2\times5}\\=4\sqrt{5}-2\sqrt{5}+3\sqrt{5}\\= (4-2+3) \sqrt{5}\\=\bold{5\sqrt{5}} [/tex]

[tex]\bold{7)\ \sqrt{20}+\sqrt{125}+ \sqrt{20}+ 2\sqrt{28}}\\=\sqrt{(4\times5)}+\sqrt{(25\times5)}+2\sqrt{(4\times5)}+2\sqrt{(4\times7)}\\=\sqrt{2^2\times5}+\sqrt{5^2\times5}+\sqrt{2^2\times5}+2\sqrt{2^2\times7}\\=2\sqrt{5}-5\sqrt{5}+2\sqrt{5}+4\sqrt{7}\\=(2-5+2) \sqrt{5}+(4\sqrt{7})\\= \bold{4\sqrt{7}-\sqrt{5}}[/tex]

[tex]\bold{8)\ 6\sqrt{72}-6\sqrt{8}+ \sqrt{20}- 3\sqrt{45}} \\=6\sqrt{(36\times2)}-6\sqrt{(4\times2)}+2\sqrt{(4\times5)}-3\sqrt{(9\times5)}\\=6\sqrt{6^2\times2}-6\sqrt{2^2\times2}+\sqrt{2^2\times5}-3\sqrt{3^2\times9}\\=(6\times6)\sqrt{2}-(6\times2)\sqrt{2}+2\sqrt{5}-(3\times3)\sqrt{5}\\=36\sqrt{2}-12\sqrt{2}+2\sqrt{5}-9\sqrt{5}\\=(36-12) \sqrt{2}+(2-9)\sqrt{5})\\= \bold{24\sqrt{2}-7\sqrt{5}}[/tex]

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