bentuk sederhana dari 4√200-2√242-5√50+10√2
Matematika
mustika71
Pertanyaan
bentuk sederhana dari 4√200-2√242-5√50+10√2
1 Jawaban
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1. Jawaban indahkim1
[tex]4 \sqrt{200} - 2 \sqrt{242} - 5 \sqrt{50} + 10 \sqrt{2} \\ = 4 \sqrt{100 \times 2} - 2 \sqrt{121 \times 2} - 5 \sqrt{25 \times 2} + 10 \sqrt{2} \\ = 4.10 \sqrt{2} - 2.11 \sqrt{2} - 5.5 \sqrt{2} + 10 \sqrt{2} \\ = 40 \sqrt{2} - 22 \sqrt{2} - 10 \sqrt{2} + 10 \sqrt{2} \\ = 18 \sqrt{2} [/tex]