Diket sin A = 3/5 , sin B = 12/13 A dan B di kuadran 1 . Nilai tan ( A - B)
Matematika
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Pertanyaan
Diket sin A = 3/5 , sin B = 12/13 A dan B di kuadran 1 . Nilai tan ( A - B)
1 Jawaban
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1. Jawaban Anonyme
jawab
A dan B di KD I
sin A = 3/5
tan A = 3/4
sin B = 12/13
tan B = 12/5
tan (A -B) = (tan A - tan B) / (1 + tan A tan B)
= (3/4 - 12/5) / ( 1 + 3/4. 12/5)
= (45- 48)/(20 + 36)
= - 3/56