jika x1 dan x2 memenuhi persamaan ^xlog 3 - ^xlog (2x - 4 + 4/x ) = 1, maka x1 + x2 =

LogAritMa

x'log 3 - x'log (2x - 4 + 4/x) = 1
x'log (3 / (2x - 4 + 4/x)) = x'log x
3 / (2x - 4 + 4/x) = x
Kalikan silang
3 = 2x² - 4x + 4
3 pindahin ke ruas kanan
2x² - 4x + 1 = 0
a = 2
b = -4
c = 1

x1 + x2 = -b/a = -(-4)/2 = 2