Matematika

Pertanyaan

2log 2x + 2log (3x-8)=

1 Jawaban


  • [tex] ^{2} log(2x) + ^{2} log(3x - 8) = \\ ^{2} log(2x(3x - 8)) = \\ ^{2} log(6x^{2} - 16) [/tex]
    GoodLuck:D

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