tlong y kwan no 3-4 ..pke Cra yaa ..makasih
Matematika
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Pertanyaan
tlong y kwan no 3-4 ..pke Cra yaa ..makasih
2 Jawaban
-
1. Jawaban ryantian17
nomor 3
6 ²log p - ²log p³ + ²log p^-3
=6 ²log p -3 ²log p -3²log p
=(6-3-3) ²log p
= 0 × ²log p =0
nomr 4
hog(-2)
= h(g(-2))
=h( (-2)²-3(-2)-9)
=h(1)
=4(1)-1
=3 -
2. Jawaban Anonyme
3) 6 2log p - 2log p^3 + 2log 1/p^3
= 2log ((p^6 / p^3 ) × 1/p^3)
= 2log 1
= 0
4) diket
a=4
b=-1
p=1
q=-3
r=-9
(h°g)(×) = (px^2 + qx + r - b) / a
(-2) = (1.-2^2 + -3.-2 + (-9) - (-1)) / 4
= ( 4 + 6 - 9 + 1 ) /4
= 2/4
= 1/2