Matematika

Pertanyaan

tlong y kwan no 3-4 ..pke Cra yaa ..makasih
tlong y kwan no 3-4 ..pke Cra yaa ..makasih

2 Jawaban

  • nomor 3

    6 ²log p - ²log p³ + ²log p^-3
    =6 ²log p -3 ²log p -3²log p
    =(6-3-3) ²log p
    = 0 × ²log p =0

    nomr 4
    hog(-2)
    = h(g(-2))
    =h( (-2)²-3(-2)-9)
    =h(1)
    =4(1)-1
    =3
  • 3) 6 2log p - 2log p^3 + 2log 1/p^3
    = 2log ((p^6 / p^3 ) × 1/p^3)
    = 2log 1
    = 0

    4) diket
    a=4
    b=-1
    p=1
    q=-3
    r=-9

    (h°g)(×) = (px^2 + qx + r - b) / a
    (-2) = (1.-2^2 + -3.-2 + (-9) - (-1)) / 4
    = ( 4 + 6 - 9 + 1 ) /4
    = 2/4
    = 1/2