Jika 3^a=4, 4^b=5, 5^c=6, 6^d=7, 7^e=8, 8^f=9, maka nilai abcdef adalah A.1 B.2 C.3 D.4 E.5 Kasih alasannya juga ya, terima kasih

a = ³log 4
b = ⁴log 5
c = ^5log 6
d = ^6log 7
e = ^7log 8
f = ^8log 9
abcdef = ³log 4 × ⁴log 5 × ^5log 6 × ^6log 7 × ^7log 8 × ^8log 9
= ³log 9
= ³log 3²
= 2.³log 3
= 2(1)
= 2
ingat aturan logaritma
^alog b × ^blog c = ^alog c