persamaan kuadrat akar-akatnya -2 dan 3

akar 1 = -2
akar 2 = 3

x1 = -2
x2 = 3

( x - x1 ) ( x - x2 ) = 0
( x - (-2))( x - 3 ) = 0
( x + 2 )( x - 3 ) = 0
[tex]{x}^{2} - 3x + 2x - 6 = 0[/tex]
[tex]{x}^{2} - x - 6 = 0[/tex]