Diket = reaksi 2No(g)->2No(g)+O2(g) mol No2= 0.6 mol (mula-mula) derajat dissosiasi =alfha No2=1/3 v= 1L ditanyakan= kc?

[tex] \alpha = \frac{mol \: reaksi}{mol \:mula^{2} } \\ \ \frac{1}{3} = \frac{mol \: reaksi}{0.6} \\ mol \: reaksi = 0.2[/tex]

reaksi :2NO2 --> 2NO + O2 mula" :_0,6_____-____-__
reaksi:_0,2_____0,2__0,1_
setmb:_0,4_____0,2__0,1_

Kc=[NO]^2[O2]/[NO2]^2
kc=[0,2]^2[0,1]/[0,4]^2
kc=0,025

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