Tentukan nilai x dari soal dibawah ini

Nomor 18

[tex] \sqrt{5x - 5} = 1 \\ { (\sqrt{5x - 5}) }^{2} = {1}^{2} \\ 5x - 5 = 1 \\ 5x = 6 \\ x = \frac{6}{5} = 1 \frac{1}{5} [/tex]
x = 1,2

Nomor 19

[tex] {( \sqrt{10} )}^{x - 2} = 0.1 \\ {( \sqrt{10} )}^{x - 2} = \frac{1}{10} \\ \\ {( {10}^{ \frac{1}{2} } )}^{x - 2} = {10}^{ - 1} \\ \\ \frac{1}{2} (x - 2) = - 1 \\ \\ x - 2 = - 2 \\ x = 0[/tex]
x = 0

Nomor 20

[tex] \sqrt{ {2}^{x + 3} } = {( \frac{1}{4} )}^{x + 4} \\ \\ ( {2}^{x + 3} ) ^{ \frac{1}{2} } = ( {2}^{ - 2} ) {}^{x + 4} \\ {2}^{ \frac{1}{2} (x + 3)} = { 2}^{ - 2(x + 4)} \\ \\ \frac{1}{2} (x + 3) = - 2(x + 4) \\ x + 3 = - 4(x + 4) \\ x + 3 = - 4x - 16 \\ 5x = - 19 \\ x = - \frac{19}{5} = - 3 \frac{4}{5} = - 3.8[/tex]
x = 3,8