Diketahui f(x-2) = x²+3x dan g(x) = 4x+1,rumus fungsi (fog) (x)=

jawab

f(x+2)  = x² + 3x
f(x+2-2)  = (x -2)² + 3( x- 2)
f(x) = x² - 4x + 4 + 3x - 6
f(x) = x² - x  - 2
g(x) = 4x + 1

fog(x) = f { g(x)}
fog(x)= f(4x +1)
fog(x)=  (4x+1)²- ( 4x +1)  - 2
fog(x) = 16x² - 8x + 1 - 4x - 1 - 2
fog(x) = 16x² -12x - 1