Pelajaran:Matematika Kelas 10 SMA Jurusan IPS Tentang:Fungsi Kuadrat TOLONG KAKAK AKU BUTUH JAWABAN KALIAN

jawab

y =  2x² - 4x + 8
a = 2---> a > 0 , titik minimum
b = - 4
c = 8

x = - b/2a
x = -(-4)/(2)(2)
x  = 4/4
x = 1

y = 2(1)² - 4(1) + 8
y = 2 - 4 + 8
y = 6

titik minimum = (x,y) =(1, 6)

2.
y= - x² -6x + 10
a= - 1 -->a< 0  maka titik maksimum
b = -6
c= 10

x = - b/2a = -(-6)/2(-1)
x = 6 / -2
x = - 3

y = - (-3)² - 6(-3) + 10
y = - 9 + 18 + 10
y = 19

titk maksimum = (-3, 19)