tolong no 1 besok dikumpul

[tex]1.)\\ \\ a.) \\ 32 {}^{n} = 2 \\ 2 {}^{5n} = 2 {}^{1} \\ 5n = 1 \\ n = \frac{1}{5} \\ \\ b.) \\ 81 {}^{n} = 3 \\ 3{}^{4n} = 3 {}^{1} \\ 4n = 1 \\ n = \frac{1}{4} \\ \\ c.) \\ 6 {}^{2n} = 216 \\ 6 {}^{2n} = 6 {}^{3} \\ 2n = 3 \\ n = \frac{3}{2} \\ \\ d.) \\ 5 {}^{4n} = 125 \\ 5 {}^{4n} = 5 {}^{3} \\ 4n = 3 \\ n = \frac{3}{4} [/tex]