diketahui akar akar persamaan kuadrat 2x²-x+3=0 adalah x¹ dan x².nilai dari 3x¹/x²+3x²/x¹

jawab

2x^2 - x + 3= 0
a= 2
b = -1
c = 3

x1+ x2 = -b/a = -(-1)/ 2  = 1/2
x1. x2 = c/a = 3/2

nilai  3x1/x2 + 2x2/ x1 =  3 ( x1/x2 + x2/x1)
= 3 ( x1^2 + x2^2) / (x1 x2)
= 3 {(x1+x2)^2 - 2 x1 x2 )}  / (x1+ x2)
= 3 {(1/2)^2 - 2(3/2)) / (3/2)
= 3 (1/4 - 3) / (3/2)
= 2 (1/4 - 3)
= 1/2 - 6
=  - 5 1/2